Wat is de discriminator van: x ^ 2 - 3x +2 = 0?

Antwoord:

# Delta = ± 1 #

Uitleg:

# Ax ^ 2 + bx + c = 0 #

# Delta = sqrt (b ^ 2-4 * a * c) "Discriminant" #

# X ^ 2-3 x + 2 = 0 #

# a = 1 ";" b = -3 ";" c = 2 #

# Delta = sqrt ((- 3) 2-4 ^ * 1 * 2) #

# Delta = sqrt (9-8) #

# Delta = sqrt 1 #

# Delta = ± 1 #