Wat is de amplitude, periode en de faseverschuiving van f (x) = 3sin (2x + pi)?

Antwoord:

# 3, pi, -pi / 2 #

Uitleg:

De standaardvorm van de #color (blauw) "sinusfunctie" # is.

#color (rood) (balk (ul (| kleur (wit) (2/2) kleur (zwart) (y = asin (bx + c) + d) kleur (wit) (02/02) |))) #

# "waarbij amplitude" = | a |, "period" = (2pi) / b #

# "faseverschuiving" = -c / b "en verticale verschuiving" = d #

# "hier" a = 3, b = 2, c = pi, d = 0 #

# "amplitude" = | 3 | = 3, "periode" = (2pi) / 2 = pi #

# "faseverschuiving" = - (pi) / 2 #

Antwoord:

De amplitude is # A = 3 #

De periode is # = Pi #

De faseverschuiving is # = - (pi) / (2) #

Uitleg:

#y = A sin (Bx + C) + D #

Amplitude is #EEN#

Periode is # (2π) / B #

Faseverschuiving is # C / B #

Verticale verschuiving is # D #

Hier hebben we

# Y = 3sin (2x + pi)) #

# Y = 3sin (2x + pi) #

De amplitude is # A = 3 #

De periode is # = (2pi) / B = (2pi) / (2) = pi #

De faseverschuiving is # = - (pi) / (2) #

grafiek {3sin (2x + pi) -5.546, 5.55, -2.773, 2.774}