Maak de waarheidstabel van de propositie ¬q [(pΛq) V ~ p]?

Maak de waarheidstabel van de propositie ¬q [(pΛq) V ~ p]?
Anonim

Antwoord:

Zie hieronder.

Uitleg:

Gegeven: #not p -> (p ^^ q) vv ~ p #

Logische operatoren:# "not p:" not p, ~ p; "en:" ^^; of: vv #

Logische tabellen, ontkenning:

#ul (| "" p | "" q | "" ~ p | "" ~ q |) #

# "" T | "" T | "" F | "" F | #

# "" T | "" F | "" F | "" T | #

# "" F | "" T | "" T | "" F | #

# "" F | "" F | "" T | "" T | #

Logische tabellen, en & of:

#ul (| "" p | "" q | "" p ^^ q "" | "" qvvq "" |) #

# | "" T | "" T | "" T "" | "" T "" | #

# | "" T | "" F | "" F "" | "" T "" | #

# | "" F | "" T | "" F "" | "" T "" | #

# | "" F | "" F | "" F "" | "" F "" | #

Logische tabellen, als dan:

#ul (| "" p | "" q | "" p-> q "" |) #

# | "" T | "" T | "" T "" | #

# | "" T | "" F | "" F "" | #

# | "" F | "" T | "" T "" | #

# | "" F | "" F | "" T "" | #

Gezien Logic-propositie deel 1:

#ul (| "" p ^^ q "" | "" ~ p "" | "" (p ^^ q) vv ~ p |) #

# | "" T "" | "" F "" | "" T "" | #

# | "" F "" | "" F "" | "" F "" | #

# | "" F "" | "" T "" | "" T "" | #

# | "" F "" | "" T "" | "" T "" | #

Given Logic proposition part 2:

#ul (| "" ~ q "" | "" (p ^^ q) vv ~ p | "" ~ q -> (p ^^ q) vv ~ p |) #

# | "" F "" | "" T "" | "" T "" | #

# | "" T "" | "" F "" | "" F "" | #

# | "" F "" | "" T "" | "" T "" | #

# | "" T "" | "" T "" | "" T "" | #