Los de volgende twee lineaire vergelijking op door substitutie en eliminatiemethode: ax + by = (a-b), bx-ay = (a-b)?

Antwoord:

# X = (a ^ 2 ^ 2-b) / (a + b ^ 2 ^ 2) # en # Y = (2AB-a ^ 2 ^ 2-b) / (a + b ^ 2 ^ 2) #

# A * (ax + by) + b * (bx-ay) = a * (a-b) + b * (a-b) #

# A ^ 2 * x + aby + b ^ 2 * x-aby = a ^ 2 + ab ab-b ^ 2 #

# (A ^ 2 + b ^ 2) * x = a ^ 2 B ^ 2 #

# X = (a ^ 2 ^ 2-b) / (a + b ^ 2 ^ 2) #

Zo, # A * (a ^ 2 ^ 2-b) / (a + b ^ 2 ^ 2) + by = a-b #

# A * (a ^ 2 B ^ 2) + * door (a ^ 2 + b ^ 2) = (a-b) * (a ^ 2 + b ^ 2) #

# A ^ 3-ab ^ 2 + (a ^ 2 + b ^ 2) * door = a ^ 3 + ab ^ 2-a ^ 2 * b-b ^ 3 #

# (A ^ 2 + b ^ 2) * door 2AB = ^ 2-a ^ 2 * b-b ^ 3 #

# Y = (2AB ^ 2-a ^ 2 * b ^ b-3) / b * (a ^ 2 + b ^ 2) #

=# (2AB-a ^ 2 ^ 2-b) / (a + b ^ 2 ^ 2) #