Wat is de afstand tussen de punten (-3,2) en (1,0)?

Antwoord:

# d = 2sqrt5 of 4.47 #

Uitleg:

De afstandsformule is # d = sqrt ((y_2-y_1) ^ 2 + (x_2-x_1) ^ 2) #

# (- 3,2) en (1,0) #

# x_1 = -3 #

# y_1 = 2 #

# x_2 = 1 #

# y_2 = 0 #

# d = sqrt ((y_2-y_1) ^ 2 + (x_2-x_1) ^ 2) #

# d = sqrt ((0-2) ^ 2 + (1 - (- 3)) ^ 2) #

# d = sqrt ((2) ^ 2 + (4) ^ 2) #

# d = sqrt (4 + 16) #

# D = sqrt (20) #

# d = 2sqrt5 of 4.47 #