Wat is de variantie van {51, 3, 9, 15, 3, -9, 20, -1, 5, 3, 2}?

Wat is de variantie van {51, 3, 9, 15, 3, -9, 20, -1, 5, 3, 2}?
Anonim

Antwoord:

variance# "" "sigma ^ 2 = 27694/121 = 228.876 #

Uitleg:

Bereken het gemiddelde # Barx # eerste

# Barx = (51 + 3 + 9 + 15 + 3 + (- 9) 20 + (- 1) + 5 + 3 + 2) / 11 = 101/11 #

variance# "" "sigma ^ 2 = (som (x-barx) ^ 2) / n #

# "" "sigma ^ 2 #

#=((51-101/11)^2+(3-101/11)^2+(9-101/11)^2+(15-101/11)^2+ (3-101/11)^2+(-9-101/11)^2+(20-101/11)^2+(-1-101/11)^2+(5-101/11)^2+ (3-101/11)^2+(2-101/11)^2)/11#

# "" "sigma ^ 2 = 27694/121 = 228.876 #

God zegene … Ik hoop dat de uitleg nuttig is.