Antwoord:
#color (blauw) (x = 4) kleur (wit) ("XX") orcolor (wit) ("XX") kleur (blauw) (x = -2) #
Uitleg:
Gegeven
#color (wit) ("XXX") 2 / (x + 6) + (2 x) / (x + 4) = (3x) / (x + 6) #
#rArr kleur (wit) ("XX") (2x) / (x + 4) = (3x-2) / (x + 6) #
cross-vermenigvuldigen:
#color (wit) ("XXX") (2x) xx (x + 6) = (3x-2) xx (x + 4) #
#rArrcolor (wit) ("XX") 2x ^ 2 + 12x = 3x ^ 2 + 10x-8 #
#rArrcolor (wit) ("XX") x ^ 2-2x-8 = 0 #
#rArrcolor (wit) ("XX") (x-4) (x + 2) = 0 #
#rArr {:(x-4 = 0, kleur (wit) ("XX") ofkleur (wit) ("XX"), x + 2 = 0), (rarrx = 4,, rarrx = -2):} #