Wat is de waarde van (2 + root5) ^ 1/3 + (2-root5) ^ 1/3?

Wat is de waarde van (2 + root5) ^ 1/3 + (2-root5) ^ 1/3?
Anonim

Antwoord:

De waarde is #-2#

Uitleg:

Laat # x = (2 + sqrt5) ^ (1/3) + (2-sqrt5) ^ (1/3) # dan

# x ^ 3 = {(2 + sqrt5) ^ (1/3) + (2-sqrt5) ^ (1/3)} ^ 3 #

Herinnering:

# (a + b) ^ 3 = a ^ 3 + b ^ 3 + 3ab (a + b), a ^ 2-b ^ 2 = (a + b) (a-b) #

en laat # a = (2 + sqrt5), b = (2-sqrt5):. ab = 4-5 = -1 #

#:. x ^ 3 = (2 + sqrt5) ^ (3 * 1/3) + (2-sqrt5) ^ (3 * 1/3) 3 (2 + sqrt5) (2-sqrt5) (2 + sqrt5 + 2-sqrt5) #

of # X ^ 3 = 2 + (sqrt5) annuleren + 2 annuleerknop (sqrt5) 3 (4-5) (2 + zonder (sqrt5) + 2 annuleerknop (sqrt5)) #

of # x ^ 3 = 4 + 3 (-1) (4) of x ^ 3 = 4 -12 of x ^ 3 = -8 # of

#x = (-8) ^ (1/3) = -2 #. De waarde is #-2# Ans