Antwoord:
Uitleg:
# 2color (rood) (x) y = -1to (1) #
#color (rood) (x) + 1 / 2y = -1 / 2om (2) #
# (2) "kan worden herschikt om" # te geven
#color (rood) (x) = - 1 / 2-1 / 2yto (3) #
# "substitute" (3) "into" (1) #
# RArr2 (-1 / 2-1 / 2y) -y = -1 #
# Rarr-1-y = -1 #
# Rarr-y = 0rArry = 0 #
# "vervang deze waarde door" (1) #
# RArr2x-0 = -1 #
# RArrx = -1/2 #
#rArr "snijpunt" = (- 1 / 2,0) # grafiek {(y-2x-1) (y + 2x + 1) = 0 -10, 10, -5, 5}