Hoe los je log (x-3) + log x = 1 op?

Hoe los je log (x-3) + log x = 1 op?
Anonim

Antwoord:

# x = 5 #

Uitleg:

Gebruik Eigenschappen: #log_b (xy) = log_b x + log_by #

# log_bx = y iff b ^ y = x #

#log (x (x-3)) = 1 # #color (wit) (xxxxxx) # 1 = log10

#log (x ^ 2-3x) = log10 #

# x ^ 2-3x ^ 1 = 10 ^ 1 #

# X ^ 2-3x-10 = 0 #

# (X-5) (x + 2) = 0 #

# x = 5 of x = -2 #