We hebben A (x) = x ^ 2-6x + 4 de vraag is factorise A (x) +5?

We hebben A (x) = x ^ 2-6x + 4 de vraag is factorise A (x) +5?
Anonim

Antwoord:

#A (x) = (x-3) * (x-3) #

Uitleg:

Wij hebben, #A (x) = x ^ + 2-6x 4 #

Zo, #color (wit) (xxx) A (x) + 5 = (x ^ 2-6x + 4) + 5 #

#rArr A (x) = x ^ 2-6x + 9 #

#rArr A (x) = (x) ^ 2 - 2 * x * 3 + (3) ^ 2 #

#rArr A (x) = (x- 3) ^ 2 #

#rArr A (x) = (x - 3) (x - 3) #

Let daar op

#color (rood) a ^ ^ 2x 2-bx + c ^ 2 = (sqrt (a ^ 2 x ^ 2) -sqrt (c ^ 2)) ^ 2 = (ax-c) ^ 2 # Waar #b = 2ac #